﻿ ﻿10 tons of boiler coal consumption

# ﻿10 tons of boiler coal consumption

### How Much Steam Produced by 1 Ton Standard Coal at a Boiler

The rated evaporation capacity of the boiler is 10 tons per hour, the calorific value of natural gas is 35.438 MJ/Nm3, and the boiler efficiency is calculated at 95%. The gas consumption per hour of the 10 ton boiler: 7 MW*3600s/35.53 MJ/Nm3/95%=746 m3/h.

### How to Calculate the Coal Quantity Used in a Power Plant

Jan 28, 2019 · The coal consumption per hour of a 10 ton coal-fired boiler is 145.5*10=1455kg/h. 3.Operating costs of six or 10 tons of coal-fired steam boilers: 1. Fuel cost: 0.2 tons of coal consumption per ton of steam, 400 RMB/ton of coal, total cost 80RMB; fuel cost of 10 tons of coal-fired steam boiler for one year: 80*10*8*360=33 Ten thousand RMB. 2.

### compare operating costs of 10 tons oil steam boilers with

How to Calculate the Coal Quantity Used in a Power Plant

### coal consumption calculation ton hour steam boiler

America's Largest Coal Power Plant Burns 11 Million Tons

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How to Calculate 10 Ton Boiler Gas Consumption

### 10 ton gas-fired steam boiler gas consumption per hour and

The calorific value of the fuel is calculated according to 35.53 MJ/Nm3, then the gas consumption of the 10 ton boiler hour = 7MW*3600s/35.53MJ/Nm3/90%=788m3/h, If the calculation is carried out for 8 hours per day, then the 10 ton gas fired boiler consumes …

### How to calculate the power consumption of the electric boiler?

Oct 15, 2009 · Coal Quantity. Since coal has a heat value of 20,000 kJ/kg, for producing one kw.hr we require (10765 / 20000) 0.538 kg of coal. This translates to (0.538 x 100 x 1,000) 53800 kg/hr (53.8 T/hr) of coal for an output of 100 MW. Coal Cost. Basic cost of coal depends on the market conditions.

### Steam Calculators: Boiler Calculator - Energy

Oct 11, 2018 · Fuel consumption gas gas consumption formula=boiler output/fuel heat value/boiler thermal efficiency. So, can calculate the gas consumption of 10 tons of gas steam boiler = 6 million kcal ÷ 0.98 ÷ 8400kcal / m3 = 716m3. Of course, the above formula is applicable to boilers under an ideal working conditions.